Draw an equiangular $\Delta PQR$ in which $PQ = 6\,cm$. Write the steps of construction.
(N/A) An equiangular triangle is an equilateral triangle where each angle is $60^{\circ}$.
Steps of construction:
$1$. Draw a line segment $PQ = 6\,cm$ using a ruler.
$2$. At point $P$,construct an angle of $60^{\circ}$ using a compass and ruler.
$3$. At point $Q$,construct an angle of $60^{\circ}$ using a compass and ruler.
$4$. Let the rays from $P$ and $Q$ intersect at point $R$.
$5$. $\Delta PQR$ is the required equiangular triangle.
Steps of construction:
$1$. Draw a line segment $PQ = 6\,cm$ using a ruler.
$2$. At point $P$,construct an angle of $60^{\circ}$ using a compass and ruler.
$3$. At point $Q$,construct an angle of $60^{\circ}$ using a compass and ruler.
$4$. Let the rays from $P$ and $Q$ intersect at point $R$.
$5$. $\Delta PQR$ is the required equiangular triangle.
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