Discuss the continuity of the $cosine, cosecant, secant$ and $cotangent$ functions.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) It is known that if $g$ and $h$ are two continuous functions,then:
$i.$ $\frac{h(x)}{g(x)}, g(x) \neq 0$ is continuous.
$ii.$ $\frac{1}{g(x)}, g(x) \neq 0$ is continuous.
$iii.$ $\frac{1}{h(x)}, h(x) \neq 0$ is continuous.
First,we prove that $g(x) = \sin x$ and $h(x) = \cos x$ are continuous functions.
For $g(x) = \sin x$,let $c$ be a real number. Put $x = c + h$. As $x \to c$,$h \to 0$.
$\lim_{x \to c} \sin x = \lim_{h \to 0} \sin(c + h) = \lim_{h \to 0} [\sin c \cos h + \cos c \sin h] = \sin c(1) + \cos c(0) = \sin c = g(c)$.
Thus,$g(x) = \sin x$ is continuous for all $x \in \mathbb{R}$.
Similarly,for $h(x) = \cos x$,$\lim_{x \to c} \cos x = \lim_{h \to 0} \cos(c + h) = \lim_{h \to 0} [\cos c \cos h - \sin c \sin h] = \cos c(1) - \sin c(0) = \cos c = h(c)$.
Thus,$h(x) = \cos x$ is continuous for all $x \in \mathbb{R}$.
Now,for the other functions:
$1.$ $\cos x$ is continuous for all $x \in \mathbb{R}$.
$2.$ $\csc x = \frac{1}{\sin x}$ is continuous where $\sin x \neq 0$,i.e.,$x \neq n\pi, n \in \mathbb{Z}$.
$3.$ $\sec x = \frac{1}{\cos x}$ is continuous where $\cos x \neq 0$,i.e.,$x \neq (2n+1)\frac{\pi}{2}, n \in \mathbb{Z}$.
$4.$ $\cot x = \frac{\cos x}{\sin x}$ is continuous where $\sin x \neq 0$,i.e.,$x \neq n\pi, n \in \mathbb{Z}$.

Explore More

Similar Questions

If the function $f(x) = \begin{cases} -2 \sin x, & x \leq \frac{-\pi}{2} \\ A \sin x+B, & \frac{-\pi}{2} < x < \frac{\pi}{2} \\ \cos x, & x \geq \frac{\pi}{2} \end{cases}$ is continuous everywhere,then the values of $A$ and $B$ are respectively

For every integer $n$,let $a_n$ and $b_n$ be real numbers. Let function $f: \mathbb{R} \rightarrow \mathbb{R}$ be given by $f(x) = \begin{cases} a_n + \sin \pi x, & \text{for } x \in [2n, 2n+1] \\ b_n + \cos \pi x, & \text{for } x \in (2n-1, 2n) \end{cases}$,for all integers $n$. If $f$ is continuous,then which of the following hold$(s)$ for all $n$?

Consider $f(x) = \left[ \frac{2(\sin x - \sin^3 x) + |\sin x - \sin^3 x|}{2(\sin x - \sin^3 x) - |\sin x - \sin^3 x|} \right]$ for $x \in (0, \pi), x \neq \frac{\pi}{2}$,and $f(\frac{\pi}{2}) = 3$,where $[ \cdot ]$ denotes the greatest integer function. Then:

If $f(x) = \begin{cases} e^x; & x \le 0 \\ |1 - x|; & x > 0 \end{cases}$,then

If the function $f(x) = \begin{cases} (1+|\cos x|)^{\frac{\lambda}{|\cos x|}} & , 0 < x < \frac{\pi}{2} \\ \mu & , x = \frac{\pi}{2} \\ e^{\frac{\cot 6x}{\cot 4x}} & , \frac{\pi}{2} < x < \pi \end{cases}$ is continuous at $x = \frac{\pi}{2}$,then $9\lambda + 6 \log_{e} \mu + \mu^6 - e^{6\lambda}$ is equal to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo