Discuss the similarities and differences between the Biot-Savart law and Coulomb's law.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Similarities and differences between the Biot-Savart law and Coulomb's law are as follows:
Similarities:
$(1)$ Both obey the inverse square law with respect to distance $(1/r^2)$.
$(2)$ Both are long-range forces/fields.
$(3)$ The principle of superposition applies to both fields.
For the static electric field, $E = \frac{kQ}{r^2}$, so $E \propto Q$.
Similarly, for the Biot-Savart law, $B = \frac{\mu_0}{4\pi} \frac{Idl \times \hat{r}}{r^2}$, so $B \propto Idl$.
Differences:
$(1)$ The magnetic field is produced by a vector source $(Id\vec{l})$, whereas the electric field is produced by a scalar source $(dq)$.
$(2)$ The electrostatic field is directed along the displacement vector $\vec{r}$ joining the source and the field point. In contrast, the magnetic field is perpendicular to the plane containing both the current element $Id\vec{l}$ and the displacement vector $\vec{r}$.
$(3)$ The Biot-Savart law depends on the angle $\theta$ between the current element and the position vector $(\sin \theta)$. For $\theta = 0^{\circ}$, the magnetic field is zero along the axis of the current element. Conversely, Coulomb's law does not depend on any angle $\theta$.

Explore More

Similar Questions

$A$ wire $A$, bent in the shape of an arc of a circle, carrying a current of $2 \, A$ and having radius $2 \, cm$, and another wire $B$, also bent in the shape of an arc of a circle, carrying a current of $3 \, A$ and having radius $4 \, cm$, are placed as shown in the figure. The ratio of the magnetic fields due to the wires $A$ and $B$ at the common centre $O$ is

$A$ circular coil of wire consisting of $100$ turns each of radius $9 \ cm$ carries a current of $0.4 \ A$. The magnitude of the magnetic field at the centre of the coil is $[\mu_0 = 12.56 \times 10^{-7} \text{ SI Units}]$.

Two insulated circular loops $A$ and $B$ of radius '$a$' carry a current of '$I$' in the directions as shown in the figure. The magnitude of the magnetic induction at the centre $O$ will be:

Current $I$ flows through a long conducting wire bent at right angles as shown in the figure. The magnetic field at a point $P$ on the right bisector of the angle $XOY$ at a distance $r$ from $O$ is

Difficult
View Solution

Which of the following graphs represents the magnetic field $(B)$ versus distance $(r)$ from the centre of a long straight conducting wire of uniform cross-sectional area carrying a steady current $I$ and having radius $a$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo