Discuss the construction and uses of a conductivity cell.
(N/A) conductivity cell is an instrument used to measure the ionic conductivity or resistivity of an electrolytic solution.
It is available in several designs,and two simple ones are shown in the diagram.
Construction: Basically,it consists of two platinum electrodes coated with platinum black (finely divided metallic $Pt$ is deposited on the electrodes electrochemically).
These electrodes have an area of cross-section equal to $A$ and are separated by a distance $l$.
Therefore,the solution confined between these electrodes acts as a column of length $l$ and area of cross-section $A$.
Uses: By using a conductivity cell,the conductivity and resistivity of an unknown electrolytic solution can be measured.
It is available in several designs,and two simple ones are shown in the diagram.
Construction: Basically,it consists of two platinum electrodes coated with platinum black (finely divided metallic $Pt$ is deposited on the electrodes electrochemically).
These electrodes have an area of cross-section equal to $A$ and are separated by a distance $l$.
Therefore,the solution confined between these electrodes acts as a column of length $l$ and area of cross-section $A$.
Uses: By using a conductivity cell,the conductivity and resistivity of an unknown electrolytic solution can be measured.
Explore More
Similar Questions
Explain the measurement and calculation of the resistivity of an electrolytic solution.
Difficult
View SolutionFor a strong electrolyte,$\Lambda_{m}$ increases slowly with dilution and can be represented by the equation $\Lambda_{m} = \Lambda_{m}^{\circ} - Ac^{1/2}$. Molar conductivity values of a solution of strong electrolyte $AB$ at $18^{\circ} C$ are given below:
$c \ [mol \ L^{-1}]$ $0.04$ $0.09$ $0.16$ $0.25$ $\Lambda_{m} \ [S \ cm^2 \ mol^{-1}]$ $96.1$ $95.7$ $95.3$ $94.9$
The value of constant $A$ based on the above data [in $S \ cm^2 \ mol^{-1} / (mol \ L^{-1})^{1/2}$] is . . . . . . .
| $c \ [mol \ L^{-1}]$ | $0.04$ | $0.09$ | $0.16$ | $0.25$ |
| $\Lambda_{m} \ [S \ cm^2 \ mol^{-1}]$ | $96.1$ | $95.7$ | $95.3$ | $94.9$ |
DifficultJEE MAIN 2026
View SolutionResistance of a conductivity cell at $298 \ K$ for $0.0100 \ M \ KCl$ is $161.8 \ \Omega$. Resistance becomes $190 \ \Omega$ when $0.005 \ M \ NaOH$ solution is filled in this cell. Calculate: $(i)$ cell constant,$(ii)$ specific conductivity for $NaOH$ solution,and $(iii)$ molar conductivity.
Difficult
View SolutionAt $25^o C$,the molar conductivities at infinite dilution of $NaOAc$ and $HCl$ in water are $91.0 \, S \, cm^2/mol$ and $426.2 \, S \, cm^2/mol$,respectively. What is the value to be added to calculate the molar conductivity of $HOAc$ at infinite dilution?
Easy
View SolutionAt $25^o C$,the molar conductivity of a $0.1 \, N \, CH_3COOH$ solution is $80 \, S \, cm^2 \, mol^{-1}$ and the molar conductivity at infinite dilution is $400 \, S \, cm^2 \, mol^{-1}$. What is the degree of dissociation $(\alpha)$ of $CH_3COOH$?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo