Dimensional formula for pressure head is

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Question

(D) Pressure head is defined as $h = \frac{P}{\rho g}$,where $P$ is pressure,$\rho$ is density,and $g$ is acceleration due to gravity.Dimensional form

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$[M^0 L^1 T^0]$

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(D) Pressure head is defined as $h = \frac{P}{ho g}$,where $P$ is pressure,$ho$ is density,and $g$ is acceleration due to gravity.Dimensional formula of pressure $P = \frac{	ext{Force}}{	ext{Area}} = \frac{[MLT^{-2}]}{[L^2]} = [ML^{-1}T^{-2}]$.Dimensional formula of density $ho = \frac{	ext{Mass}}{	ext{Volume}} = \frac{[M]}{[L^3]} = [ML^{-3}]$.Dimensional formula of acceleration due to gravity $g = [LT^{-2}]$.Substituting these into the formula for pressure head:$[h] = \frac{[ML^{-1}T^{-2}]}{[ML^{-3}] \cdot [LT^{-2}]}$$[h] = \frac{[ML^{-1}T^{-2}]}{[ML^{-2}T^{-2}]}$$[h] = [M^0 L^1 T^0]$.Thus,the correct option is $D$.

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