The dimension of R (Resistance) is: | vedclass

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Question

(B) According to Ohm's law,$R = \frac{V}{I}$.First,find the dimensions of potential difference $(V)$: $V = \frac{W}{q} = \frac{[M L^2 T^{-2}]}{[A T]}

Vedclass · Accepted Answer

$M L^2 T^{-3} A^{-2}$

Vedclass · Answer

(B) According to Ohm's law,$R = \frac{V}{I}$.First,find the dimensions of potential difference $(V)$: $V = \frac{W}{q} = \frac{[M L^2 T^{-2}]}{[A T]} = [M L^2 T^{-3} A^{-1}]$.Now,substitute the dimensions of $V$ and $I$ into the formula for $R$:$R = \frac{[M L^2 T^{-3} A^{-1}]}{[A]} = [M L^2 T^{-3} A^{-2}]$.Therefore,the correct option is $B$.

The dimension of $R$ (Resistance) is:

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