Determine whether the following relation is reflexive,symmetric,and transitive:
Relation $R$ in the set $Z$ of all integers defined as $R = \{(x, y) : x - y \text{ is an integer}\}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Given $R = \{(x, y) : x - y \text{ is an integer}\}$ for $x, y \in Z$.
$1$. Reflexive: For any $x \in Z$,$x - x = 0$,which is an integer. Thus,$(x, x) \in R$. Therefore,$R$ is reflexive.
$2$. Symmetric: Let $(x, y) \in R$. Then $x - y$ is an integer. This implies $-(x - y) = y - x$ is also an integer. Thus,$(y, x) \in R$. Therefore,$R$ is symmetric.
$3$. Transitive: Let $(x, y) \in R$ and $(y, z) \in R$. Then $x - y$ and $y - z$ are integers. Their sum $(x - y) + (y - z) = x - z$ is also an integer. Thus,$(x, z) \in R$. Therefore,$R$ is transitive.
Conclusion: $R$ is reflexive,symmetric,and transitive.

Explore More

Similar Questions

Let $R$ be a relation on the set $N$ defined by $\{(x, y) | x, y \in N, 2x + y = 41\}$. Then $R$ is

Let $A = \{1, 2, 3\}$. The number of equivalence relations on $A$ containing $(1, 2)$ is . . . . . . .

Show that the relation $R$ in the set $Z$ of integers given by $R = \{(a, b) : 2 \text{ divides } a - b\}$ is an equivalence relation.

Give an example of a relation which is transitive but neither reflexive nor symmetric.

Show that the relation $R$ defined in the set $A$ of all polygons as $R = \{(P_{1}, P_{2}) : P_{1} \text{ and } P_{2} \text{ have the same number of sides}\}$,is an equivalence relation. What is the set of all elements in $A$ related to the right-angled triangle $T$ with sides $3, 4, \text{ and } 5$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo