Determine the value of x. If x = frac{(943 + | vedclass

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Question

(A) We use the algebraic identity $(a + b)^{2} - (a - b)^{2} = 4ab$.Here,let $a = 943$ and $b = 864$.Then the numerator becomes $4 	imes 943 	imes 8

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$1$

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(A) We use the algebraic identity $(a + b)^{2} - (a - b)^{2} = 4ab$.Here,let $a = 943$ and $b = 864$.Then the numerator becomes $4 	imes 943 	imes 864$.The denominator is $1886 	imes 1728$.Note that $1886 = 2 	imes 943$ and $1728 = 2 	imes 864$.Substituting these into the expression for $x$:$x = \frac{4 	imes 943 	imes 864}{(2 	imes 943) 	imes (2 	imes 864)}$$x = \frac{4 	imes 943 	imes 864}{4 	imes 943 	imes 864}$$x = 1$.

Determine the value of $x$. If $x = \frac{(943 + 864)^{2} - (943 - 864)^{2}}{(1886 \times 1728)}$

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