Derive the molecular formula for Ammonium carbonate.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) To derive the molecular formula for Ammonium carbonate,we follow these steps:
$1$. Identify the ions and their respective charges:
- Ammonium ion: $NH_4^+$ (charge = $+1$)
- Carbonate ion: $CO_3^{2-}$ (charge = $-2$)
$2$. Write the symbols and their charges side-by-side:
- Symbol: $NH_4$ and $CO_3$
- Charge: $+1$ and $-2$
$3$. Use the criss-cross method to balance the charges:
- The charge of the Ammonium ion $(+1)$ becomes the subscript for the Carbonate ion.
- The charge of the Carbonate ion $(-2)$ becomes the subscript for the Ammonium ion.
$4$. Combine them to form the neutral compound:
- Since we need two Ammonium ions to balance one Carbonate ion,the formula is $(NH_4)_2CO_3$.

Explore More

Similar Questions

$(a)$ State the law of conservation of mass.
$(b)$ What mass of silver nitrate will react with $5.85 \, g$ of sodium chloride to produce $14.35 \, g$ of silver chloride and $8.5 \, g$ of sodium nitrate,if the law of conservation of mass is true?

$(a)$ $A$ sample of vitamin $C$ is known to contain $2.58 \times 10^{24}$ oxygen atoms. How many moles of oxygen atoms are present in the sample?
$(b)$ Write one word for the following:
$(i)$ In a balanced chemical equation,the sum of the masses of reactants and products remains unchanged.
$(ii)$ $A$ group of atoms carrying a fixed charge on them.
$(c)$ Write chemical formulae of the following compounds:
$(i)$ Sodium phosphate
$(ii)$ Ammonium carbonate

State whether the following statement is true or false:
Sodium shows valency of $Na^+$ and $Na^{2+}$.

Which of the following has the maximum number of atoms?

Which of the following statements is not true about an atom?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo