Define an equipotential surface.
(N/A) An equipotential surface is a surface with a constant value of electric potential at all points on it.
For any charge distribution,the electric potential $V$ is the same at every point on an equipotential surface.
Consequently,the potential difference between any two points on such a surface is zero $(V_A - V_B = 0)$.
Since the work done in moving a test charge $q_0$ between two points on an equipotential surface is given by $W = q_0(V_A - V_B)$,it follows that no work is done in moving a charge along an equipotential surface.
Furthermore,the electric field lines are always perpendicular to the equipotential surface at every point.
For any charge distribution,the electric potential $V$ is the same at every point on an equipotential surface.
Consequently,the potential difference between any two points on such a surface is zero $(V_A - V_B = 0)$.
Since the work done in moving a test charge $q_0$ between two points on an equipotential surface is given by $W = q_0(V_A - V_B)$,it follows that no work is done in moving a charge along an equipotential surface.
Furthermore,the electric field lines are always perpendicular to the equipotential surface at every point.
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The angle between the electric lines of force and the equipotential surface is (in $^{\circ}$)
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View SolutionThe figure shows a family of parallel equipotential surfaces and four paths along which an electron is made to move from one surface to another.
$(I)$ What is the direction of the electric field?
$(II)$ Rank the paths according to the magnitude of work done,greatest first.
$(I)$ What is the direction of the electric field?
$(II)$ Rank the paths according to the magnitude of work done,greatest first.
Medium
View SolutionGiven below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: Work done by an electric field on moving a positive charge on an equipotential surface is always zero.
Reason $(R)$: Electric lines of force are always perpendicular to equipotential surfaces.
In the light of the above statements,choose the most appropriate answer from the options given below:
Assertion $(A)$: Work done by an electric field on moving a positive charge on an equipotential surface is always zero.
Reason $(R)$: Electric lines of force are always perpendicular to equipotential surfaces.
In the light of the above statements,choose the most appropriate answer from the options given below:
DifficultJEE MAIN 2024
View SolutionWork done in moving a positive charge on an equipotential surface is
Easy
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