Deduce the structure of (A).(A) C_{8}H_{10} | vedclass

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(B) $1$. The reaction sequence starts with $(A)$ having molecular formula $C_{8}H_{10}$.$2$. Oxidation with $KMnO_{4}$ converts alkyl side chains on a

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(B) $1$. The reaction sequence starts with $(A)$ having molecular formula $C_{8}H_{10}$.$2$. Oxidation with $KMnO_{4}$ converts alkyl side chains on a benzene ring into carboxylic acid groups $(-COOH)$.$3$. $(B)$ has the formula $C_{8}H_{6}O_{4}$,which corresponds to a dicarboxylic acid (phthalic acid derivative).$4$. The final step is the bromination of $(B)$ in the presence of $Fe$ to give $(C)$ as a single product.$5$. For a dicarboxylic acid to yield only one monobrominated product,the starting material $(B)$ must be terephthalic acid (benzene$-1,4-$dicarboxylic acid),where all four remaining positions on the ring are equivalent.$6$. Therefore,$(A)$ must be $p$-xylene ($1$,$4$-dimethylbenzene),which corresponds to the structure shown in option $(B)$.

Deduce the structure of $(A)$.
$(A) \ C_{8}H_{10}$ $\xrightarrow{KMnO_{4}} (B) \ C_{8}H_{6}O_{4}$ $\xrightarrow[Fe]{Br_{2}} C_{8}H_{5}BrO_{4} (C)$ (one-product only)

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Deduce the structure of $(A)$.$(A) \ C_{8}H_{10}$ $\xrightarrow{KMnO_{4}} (B) \ C_{8}H_{6}O_{4}$ $\xrightarrow[Fe]{Br_{2}} C_{8}H_{5}BrO_{4} (C)$ (one-product only)