(B) $KMnO_4$ acts as a strong oxidizing agent in acidic medium and $H_2O_2$ acts as a reducing agent.The reaction is: $2MnO_4^- + 6H^+ + 5H_2O_2 \righ

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(B) $KMnO_4$ acts as a strong oxidizing agent in acidic medium and $H_2O_2$ acts as a reducing agent.The reaction is: $2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow 2Mn^{2+} + 5O_2 + 8H_2O$.In this reaction,the manganate$(VII)$ ions $(MnO_4^-)$ are reduced to manganese$(II)$ ions $(Mn^{2+})$,which causes the decolourisation of the purple solution.

Class 11 Chemistry Hydrogen Hydrogen peroxide

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Decolourisation of acidified potassium permanganate occurs when $H_2O_2$ is added to it,this is due to

A
Oxidation of $KMnO_4$
B
Reduction of $KMnO_4$
C
Both oxidation & reduction of $KMnO_4$
D
None of the above

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Hydrogen

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Hydrogen peroxide

The normality of $10$ $V$ (volume) hydrogen peroxide is:

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Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases $H_2O_2$ acts as a reducing agent in acidic medium?

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In which of the following reactions does $H_2O_2$ act as a reducing agent?

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What is the product of the reaction of $H_2O_2$ with $Cl_2$?

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Assertion $(A)$: The colour of old lead paintings can be restored by washing them with a dilute solution of $H_2O_2$.
Reason $(R)$: Hydrogen peroxide reduces $PbS$ to $Pb$.

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Decolourisation of acidified potassium permanganate occurs when $H_2O_2$ is added to it,this is due to

Similar Questions

The normality of $10$ $V$ (volume) hydrogen peroxide is:

Hydrogen peroxide acts both as an oxidising and as a reducing agent depending upon the nature of the reacting species. In which of the following cases $H_2O_2$ acts as a reducing agent in acidic medium?

In which of the following reactions does $H_2O_2$ act as a reducing agent?

What is the product of the reaction of $H_2O_2$ with $Cl_2$?

Assertion $(A)$: The colour of old lead paintings can be restored by washing them with a dilute solution of $H_2O_2$.Reason $(R)$: Hydrogen peroxide reduces $PbS$ to $Pb$.

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Assertion $(A)$: The colour of old lead paintings can be restored by washing them with a dilute solution of $H_2O_2$.
Reason $(R)$: Hydrogen peroxide reduces $PbS$ to $Pb$.