The de-Broglie wavelength of a body of mass 1 | vedclass

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Question

(A) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given: $h = 6.63 	imes 10^{-34} \ J \cdot s$,$m = 1 \ kg$,$v

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$3.3 	imes 10^{-27} \ \mathring{A}$

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(A) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$.Given: $h = 6.63 	imes 10^{-34} \ J \cdot s$,$m = 1 \ kg$,$v = 2000 \ m/s$.Substituting the values: $\lambda = \frac{6.63 	imes 10^{-34}}{1 	imes 2000} = \frac{6.63}{2} 	imes 10^{-37} \ m = 3.315 	imes 10^{-37} \ m$.Since $1 \ \mathring{A} = 10^{-10} \ m$,we convert the wavelength to $\mathring{A}$:$\lambda = 3.315 	imes 10^{-37} \ m = 3.315 	imes 10^{-27} \ \mathring{A}$.Rounding to one decimal place,we get $3.3 	imes 10^{-27} \ \mathring{A}$.

The de-Broglie wavelength of a body of mass $1 \ kg$ moving with a velocity of $2000 \ m/s$ is:

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