Cyclopentanol on reaction with NaH followed b | vedclass

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Question

(D) The reaction of cyclopentanol with $NaH$ forms a sodium alkoxide intermediate. This alkoxide then reacts with $CS_{2}$ to form a sodium xanthate s

Vedclass · Accepted Answer

xanthate

Vedclass · Answer

(D) The reaction of cyclopentanol with $NaH$ forms a sodium alkoxide intermediate. This alkoxide then reacts with $CS_{2}$ to form a sodium xanthate salt. Finally,the reaction with $CH_{3}I$ (methyl iodide) results in the formation of a methyl xanthate ester. This sequence is known as the Chugaev elimination precursor synthesis. Therefore,the product is a xanthate. Thus,option $(d)$ is the correct answer.

Cyclopentanol on reaction with $NaH$ followed by $CS_{2}$ and $CH_{3}I$ produces a/an

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