Current in a coil changes from 4 ,A to zero i | vedclass

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(C) The magnitude of the induced emf in a coil is given by the formula: $|e| = L \left| \frac{dI}{dt} \right|$.Given:Initial current $I_1 = 4 \,A$.Fin

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$2.5$

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(C) The magnitude of the induced emf in a coil is given by the formula: $|e| = L \left| \frac{dI}{dt} ight|$.Given:Initial current $I_1 = 4 \,A$.Final current $I_2 = 0 \,A$.Change in current $dI = I_2 - I_1 = 0 - 4 = -4 \,A$.Time interval $dt = 0.1 \,s$.Induced emf $|e| = 100 \,V$.Substituting these values into the formula:$100 = L 	imes \frac{|-4|}{0.1}$.$100 = L 	imes \frac{4}{0.1}$.$100 = L 	imes 40$.$L = \frac{100}{40} = 2.5 \,H$.Therefore,the self-inductance of the coil is $2.5 \,H$.

Current in a coil changes from $4 \,A$ to zero in $0.1 \,s$ and the emf induced is $100 \,V$. The self inductance of the coil is (in $\,H$)

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