Correct statement for CeO_2 is/are:1. It is d | vedclass

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(D) In $CeO_2$,Cerium is in the $+4$ oxidation state $(Ce^{4+})$.The electronic configuration of $Ce$ $(Z=58)$ is $[Xe] 4f^1 5d^1 6s^2$. Therefore,$Ce

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$1, 2$ and $3$

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(D) In $CeO_2$,Cerium is in the $+4$ oxidation state $(Ce^{4+})$.The electronic configuration of $Ce$ $(Z=58)$ is $[Xe] 4f^1 5d^1 6s^2$. Therefore,$Ce^{4+}$ has the configuration $[Xe] 4f^0$.$1$. Since there are no unpaired electrons in the $4f$ orbital,$CeO_2$ is diamagnetic. This statement is correct.$2$. $Ce^{4+}$ has a strong tendency to gain an electron to return to the more stable $+3$ oxidation state $(Ce^{3+})$. Thus,it acts as a good oxidising agent. This statement is correct.$3$. Due to the absence of $f-f$ transitions ($4f^0$ configuration),$CeO_2$ is colourless. This statement is correct.Therefore,all three statements are correct.

Correct statement for $CeO_2$ is/are:
$1$. It is diamagnetic in nature.
$2$. It is a good oxidising agent.
$3$. It is a colourless compound.

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Correct statement for $CeO_2$ is/are:$1$. It is diamagnetic in nature.$2$. It is a good oxidising agent.$3$. It is a colourless compound.