The correct solubility order is:

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(D) The solubility of ionic compounds is determined by the balance between lattice energy and hydration energy. For compounds with small,highly charge

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$Ag_2O > Ag_2S$

Vedclass · Answer

(D) The solubility of ionic compounds is determined by the balance between lattice energy and hydration energy. For compounds with small,highly charged anions (like $F^-$),the lattice energy is very high due to strong electrostatic attraction,making them less soluble compared to compounds with larger,less charged anions (like $Cl^-$). In the case of $Ag_2O$ and $Ag_2S$,$Ag_2O$ is more soluble than $Ag_2S$ because the lattice energy of $Ag_2S$ is significantly higher due to the greater polarizability of the $S^{2-}$ ion compared to $O^{2-}$,which increases the covalent character and decreases solubility. Therefore,the correct order is $Ag_2O > Ag_2S$.

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