Correct sequence of reagents for the conversi | vedclass

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(D) The direct nitration of aniline with $HNO_3 / H_2SO_4$ leads to the formation of $m$-nitroaniline due to the protonation of the $-NH_2$ group to $

Vedclass · Accepted Answer

$(CH_3CO)_2O / 	ext{Pyridine}$,$HNO_3 / H_2SO_4$ at $288 \ K$,$OH^-$ or $H^+$

Vedclass · Answer

(D) The direct nitration of aniline with $HNO_3 / H_2SO_4$ leads to the formation of $m$-nitroaniline due to the protonation of the $-NH_2$ group to $-NH_3^+$,which is meta-directing. To obtain $p$-nitroaniline,the $-NH_2$ group must first be protected by acetylation using $(CH_3CO)_2O / 	ext{Pyridine}$ to form acetanilide. The acetanilide group $(-NHCOCH_3)$ is ortho/para-directing and less activating,which allows for controlled nitration at the para position using $HNO_3 / H_2SO_4$ at $288 \ K$. Finally,the acetyl group is removed by hydrolysis using $OH^-$ or $H^+$ to yield $p$-nitroaniline. Thus,the correct sequence is: $(CH_3CO)_2O / 	ext{Pyridine}$,$HNO_3 / H_2SO_4$ at $288 \ K$,$OH^-$ or $H^+$.

Correct sequence of reagents for the conversion shown in the image is $-$

Similar Questions

Given below are two statements:
Statement $I$: Pure Aniline and other arylamines are usually colourless.
Statement $II$: Arylamines get coloured on storage due to atmospheric reduction.
In the light of the above statements,choose the most appropriate answer from the options given below:

Consider the following statements:
Statement-$I$: $CH_3NH_2$ is more basic than $NH_3$,but $C_6H_5NH_2$ is less basic than $NH_3$.
Statement-$II$: The order of basic strength of ethyl-substituted amines in the aqueous phase follows the order $(C_2H_5)_2NH > (C_2H_5)_3N > C_2H_5NH_2$.

Identify $Z$ in the following sequence of reactions.

Which of the following products is a Schiff base?
$C_2H_5NH_2 \xrightarrow{HNO_2} a$
$C_2H_5NH_2 \xrightarrow{C_6H_5CHO} b$
$C_2H_5NH_2 \xrightarrow{NOCl} c$
$C_2H_5NH_2 \xrightarrow{C_6H_5SO_2Cl} d$

Identify the strongest base from the given compounds.

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