The correct order of the rate of EAS (electro | vedclass

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(A) The rate of $EAS$ depends on the electron density of the benzene ring. Electron-donating groups increase the rate,while electron-withdrawing group

Vedclass · Accepted Answer

$C > D > B > A$

Vedclass · Answer

(A) The rate of $EAS$ depends on the electron density of the benzene ring. Electron-donating groups increase the rate,while electron-withdrawing groups decrease it.$1$. $-CH_3$ (in $C$) is an electron-donating group ($+I$ and hyperconjugation),which activates the ring.$2$. Benzene $(D)$ has no substituent.$3$. $-Cl$ (in $B$) is a deactivating group due to its strong $-I$ effect,although it is ortho/para directing.$4$. $-NO_2$ (in $A$) is a strongly deactivating group due to its strong $-I$ and $-M$ effects.Therefore,the order of reactivity is $C$ (activated) $> D$ (benzene) $> B$ (weakly deactivated) $> A$ (strongly deactivated).The correct order is $C > D > B > A$.

The correct order of the rate of $EAS$ (electrophilic aromatic substitution) for the given compounds is:

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