Which of the following represents the correct order?

The electronic configurations of four elements are:
$I. [Xe] \, 6s^1$
$II. [Xe] \, 4f^{14} \, 5d^1 \, 6s^2$
$III. [Ar] \, 4s^2 \, 4p^5$
$IV. [Ar] \, 3d^7 \, 4s^2$
Select the incorrect statement about these elements.

Assign true $(T)$ and false $(F)$ for the following statements and select the correct option for your answer:
$(a) \, IP$ of $O_{(g)}$ is less than $IP$ of $O_{(g)}^{-}$
$(b) \, IP$ of $Ne_{(g)}$ is greater than $IP$ of $Ne_{(g)}^{+}$
$(c) \, EA$ of $O_{(g)}^{+}$ is greater than $EA$ of $O_{(g)}$
$(d) \, IP$ of $N_{(g)}$ is greater than $IP$ of $N_{(g)}^{+}$

Which of the following order$(s)$ is/are correct?
$(1) Li < Be < B < C$ $(IE_1)$
$(2) Li < Na < K < Rb < Cs$ (Reducing power in gaseous state)
$(3) Li^{+} < Na^{+} < K^{+} < Rb^{+} < Cs^{+}$ (Ionic mobility in aqueous solution)
$(4) S > Se > Te > O$ $(EA)$

Consider the following statements:
$I.$ The radius of an anion is larger than that of the parent atom.
$II.$ The ionization energy generally increases with increasing atomic number in a period.
$III.$ The electronegativity of an element is the tendency of an isolated atom to attract an electron.
Which of the above statements is/are correct?

Count the number of properties which have higher value for '$O$' atom than that of '$S$': Ionisation potential, Electron affinity, Covalent radius, Electronegativity.