Consult the table of standard electrode potentials and suggest three substances that can oxidise ferrous ions under suitable conditions.
(N/A) Substances that are stronger oxidizing agents than ferrous ions can oxidize ferrous ions.
The oxidation reaction is: $Fe^{2+} \to Fe^{3+} + e^{-}; E^{\Theta} = -0.77 \ V$.
This implies that any substance with a standard reduction potential higher than $+0.77 \ V$ can oxidize ferrous ions $(Fe^{2+})$ to ferric ions $(Fe^{3+})$.
Three substances that satisfy this condition are $F_{2}$ $(E^{\Theta} = +2.87 \ V)$,$Cl_{2}$ $(E^{\Theta} = +1.36 \ V)$,and $O_{2}$ $(E^{\Theta} = +1.23 \ V)$.
The oxidation reaction is: $Fe^{2+} \to Fe^{3+} + e^{-}; E^{\Theta} = -0.77 \ V$.
This implies that any substance with a standard reduction potential higher than $+0.77 \ V$ can oxidize ferrous ions $(Fe^{2+})$ to ferric ions $(Fe^{3+})$.
Three substances that satisfy this condition are $F_{2}$ $(E^{\Theta} = +2.87 \ V)$,$Cl_{2}$ $(E^{\Theta} = +1.36 \ V)$,and $O_{2}$ $(E^{\Theta} = +1.23 \ V)$.
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View SolutionGiven standard electrode potentials:
$Fe^{2+} + 2e^- \to Fe; E^o = -0.440 \ V$
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$Fe^{2+} + 2e^- \to Fe; E^o = -0.440 \ V$
$Fe^{3+} + 3e^- \to Fe; E^o = -0.036 \ V$
The standard electrode potential $(E^o)$ for $Fe^{3+} + e^- \to Fe^{2+}$ is .............. $V$.
DifficultAIIMS 1982
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