Consider the situation shown in the figure. T | vedclass

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(B) The motional electromotive force $(EMF)$ induced in a conductor moving in a magnetic field is given by $\varepsilon = \int (\vec{v} 	imes \vec{B}

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Remain the same

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(B) The motional electromotive force $(EMF)$ induced in a conductor moving in a magnetic field is given by $\varepsilon = \int (\vec{v} 	imes \vec{B}) \cdot d\vec{l}$.For a conductor moving with constant velocity $\vec{v}$ in a uniform magnetic field $\vec{B}$,this simplifies to $\varepsilon = \vec{v} 	imes \vec{B} \cdot \vec{L}_{eff}$,where $\vec{L}_{eff}$ is the effective length vector connecting the two ends of the conductor.In both cases (straight wire $AB$ and a semicircular wire connecting points $A$ and $B$),the effective length vector $\vec{L}_{eff}$ is the same,as it is the straight-line distance between the points of contact on the rails.Since the velocity $V$,magnetic field $B$,and effective length $L_{eff}$ remain unchanged,the induced $EMF$ $\varepsilon = B V L_{eff}$ remains the same.Consequently,the induced current $I = \varepsilon / R$ also remains the same.

Consider the situation shown in the figure. The wire $AB$ is sliding on the fixed rails with a constant velocity $V$. If the wire $AB$ is replaced by a semicircular wire of the same end-to-end distance,the magnitude of the induced current will:

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