Consider the reaction:KOH + O_3 to coloured s | vedclass

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(B) The reaction is: $2KOH + 2O_3 	o 2KO_3 + O_2 + H_2O$.Here,$(a)$ is $KO_3$ (potassium ozonide) and $(b)$ is $O_2$ (oxygen gas).$KO_3$ contains the

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$(b)$ does not react directly with $Xe$

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(B) The reaction is: $2KOH + 2O_3 	o 2KO_3 + O_2 + H_2O$.Here,$(a)$ is $KO_3$ (potassium ozonide) and $(b)$ is $O_2$ (oxygen gas).$KO_3$ contains the ozonide ion $(O_3^-)$,which has one unpaired electron,making it paramagnetic.$KO_3$ reacts with $HCl$ to produce $O_2$ gas: $2KO_3 + 2HCl 	o 2KCl + 2O_2 + H_2O$.$O_2$ does not react directly with $Xe$ under standard conditions.Therefore,the statement '$(b)$ does not react directly with $Xe$' is correct.

List-$I$	List-$II$
$(a)$ $NaOH$	$(i)$ Acidic
$(b)$ $Be(OH)_{2}$	$(ii)$ Basic
$(c)$ $Ca(OH)_{2}$	$(iii)$ Amphoteric
$(d)$ $B(OH)_{3}$
$(e)$ $Al(OH)_{3}$

Consider the reaction:
$KOH + O_3 \to$ coloured solid $(a) +$ Gas $(b) + H_2O$
Select the $CORRECT$ statement.

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The frequency of the radiation emitted by alkali metals in the flame test follows the order:

Match List-$I$ with List-$II$ :

List-$I$ List-$II$

$(a)$ $NaOH$ $(i)$ Acidic

$(b)$ $Be(OH)_{2}$ $(ii)$ Basic

$(c)$ $Ca(OH)_{2}$ $(iii)$ Amphoteric

$(d)$ $B(OH)_{3}$

$(e)$ $Al(OH)_{3}$

Choose the most appropriate answer from the options given below :

In the Solvay ammonia process,why does sodium bicarbonate precipitate?

What is the order of relative degree of hydration for alkali metal ions?

In certain properties,lithium differs from other alkali metals. The main reason for this is:

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Consider the reaction:$KOH + O_3 \to$ coloured solid $(a) +$ Gas $(b) + H_2O$Select the $CORRECT$ statement.