Consider the reaction4 HNO_{3(ell)} + 3 KCl_{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The balanced chemical equation is:$4 HNO_{3} + 3 KCl \rightarrow Cl_{2} + NOCl + 2 H_{2}O + 3 KNO_{3}$Calculate the molar masses:$M(HNO_{3}) = 1 +

Vedclass · Accepted Answer

$91.5$

Vedclass · Answer

(C) The balanced chemical equation is:$4 HNO_{3} + 3 KCl ightarrow Cl_{2} + NOCl + 2 H_{2}O + 3 KNO_{3}$Calculate the molar masses:$M(HNO_{3}) = 1 + 14 + (3 	imes 16) = 63 \ g/mol$$M(KNO_{3}) = 39 + 14 + (3 	imes 16) = 101 \ g/mol$From the stoichiometry,$3 \ moles$ of $KNO_{3}$ are produced by $4 \ moles$ of $HNO_{3}$.Number of moles of $KNO_{3}$ produced = $\frac{110.0 \ g}{101 \ g/mol} \approx 1.089 \ mol$.Moles of $HNO_{3}$ required = $\frac{4}{3} 	imes (	ext{moles of } KNO_{3}) = \frac{4}{3} 	imes \frac{110}{101} \approx 1.452 \ mol$.Mass of $HNO_{3}$ required = $1.452 \ mol 	imes 63 \ g/mol = 91.5 \ g$.

Consider the reaction
$4 HNO_{3(\ell)} + 3 KCl_{(s)} \rightarrow Cl_{2(g)} + NOCl_{(g)} + 2 H_{2}O_{(g)} + 3 KNO_{3(s)}$
The amount of $HNO_{3}$ required to produce $110.0 \ g$ of $KNO_{3}$ is $...... \ g$.
(Given: Atomic masses of $H, O, N$ and $K$ are $1, 16, 14$ and $39$ respectively.)

Similar Questions

$150 \ g$ $CaCO_3$ sample was taken. On its complete decomposition $56 \ g$ $CaO$ is produced. The $\%$ purity of the sample is .............. $\%$

$3 \ L$ mixture of $C_2H_6$ and $C_3H_8$ produces $8 \ L$ of $CO_2$ upon complete combustion. Find the volume of $C_2H_6$ in the mixture.

Volume of air required to completely burn $10 \ L$ of $C_2H_4$ is ................ $L$ (assume all volumes are measured at the same temperature and pressure,and air contains $20\%$ oxygen by volume).

How many kilograms of $CaCO_3$ must be heated to obtain $56$ kilograms of $CaO$? [Atomic masses: $Ca = 40, C = 12, O = 16$]

$20 \ mL$ of $CO_2$ gas are passed over excess of red hot coke. The volume of $CO$ evolved is ............. $mL$.
$CO_{2(g)} + C_{(s)} \to 2CO_{(g)}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the reaction$4 HNO_{3(\ell)} + 3 KCl_{(s)} \rightarrow Cl_{2(g)} + NOCl_{(g)} + 2 H_{2}O_{(g)} + 3 KNO_{3(s)}$The amount of $HNO_{3}$ required to produce $110.0 \ g$ of $KNO_{3}$ is $...... \ g$.(Given: Atomic masses of $H, O, N$ and $K$ are $1, 16, 14$ and $39$ respectively.)