Consider the reaction sequence below:Anisole | vedclass

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(C) $1$. The reaction of anisole with succinic anhydride in the presence of $AlCl_3$ (Friedel-Crafts acylation) occurs primarily at the para-position

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$6-$methoxytetralin

Vedclass · Answer

(C) $1$. The reaction of anisole with succinic anhydride in the presence of $AlCl_3$ (Friedel-Crafts acylation) occurs primarily at the para-position due to the activating and ortho/para-directing nature of the $-OCH_3$ group. This yields $4-(4-methoxyphenyl)-4-oxobutanoic$ acid as intermediate $A$.$2$. Clemmensen's reduction $(Zn-Hg/conc. HCl)$ reduces the ketone group to a methylene group,yielding $4-(4-methoxyphenyl)butanoic$ acid.$3$. Subsequent cyclization (often using $PCl_5$ followed by $AlCl_3$ or polyphosphoric acid) leads to the formation of $6-methoxytetralone$. Further reduction of the ketone gives $6-methoxytetralin$.$4$. Based on the provided options and the final structure in the solution image,the product $X$ is $6-methoxytetralin$.

Consider the reaction sequence below:
Anisole $\xrightarrow[AlCl_3]{\text{Succinic anhydride}} A$ $\xrightarrow[\text{Clemmensen's reduction}]{\text{Cyclization}} X$
Identify $X$.

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Consider the reaction sequence below:Anisole $\xrightarrow[AlCl_3]{\text{Succinic anhydride}} A$ $\xrightarrow[\text{Clemmensen's reduction}]{\text{Cyclization}} X$Identify $X$.