Medium
Consider the reaction $2 \ A + 2 \ B \rightarrow C + 2 \ D$. If the concentration of $A$ is doubled at constant $B$,the rate increases by a factor of $4$. If the concentration of $B$ is doubled at constant $A$,the rate is doubled. What is the rate law?
- A$r = k[A]^{2}[B]^{2}$
- B$r = k[A]^{4}[B]^{2}$
- C$r = k[A][B]^{2}$
- D$r = k[A]^{2}[B]$
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Similar Questions
The reaction,$X + 2Y + Z \to N$ occurs by the following mechanism:
$(i)$ $X + Y \rightleftharpoons M$ (very rapid equilibrium)
$(ii)$ $M + Z \to P$ (slow)
$(iii)$ $P + Y \to N$ (very fast)
What is the rate law for this reaction?
$(i)$ $X + Y \rightleftharpoons M$ (very rapid equilibrium)
$(ii)$ $M + Z \to P$ (slow)
$(iii)$ $P + Y \to N$ (very fast)
What is the rate law for this reaction?
Difficult
View SolutionThe rate law for the reaction $A + B \rightarrow \text{product}$ is $\text{rate} = k[A][B]$. When will the rate of reaction increase by a factor of $2$?
The half-life period of a gaseous reactant undergoing thermal decomposition was measured for various initial pressures $P_0$ as follows:
$P_0 \text{ (mmHg)}$ $250$ $300$ $t_{1/2} \text{ (minutes)}$ $135$ $112.5$
The order of reaction is -
| $P_0 \text{ (mmHg)}$ | $250$ | $300$ |
| $t_{1/2} \text{ (minutes)}$ | $135$ | $112.5$ |
The order of reaction is -
Medium
View SolutionFor any reaction,the rate constant $K = 2.3 \times 10^{-5} \ mol^{-3/2} \ L^{3/2} \ S^{-1}$. The order of the reaction is . . . . . . .
Define the following terms:
$(1)$ Elementary reaction
$(2)$ Complex reaction
$(1)$ Elementary reaction
$(2)$ Complex reaction
Medium
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