Consider the isomers of the hydrocarbon with molecular formula $C_5H_{10}$. These isomers do not decolourise $KMnO_4$ solution. These isomers are subjected to chlorination with chlorine in the presence of light to give monochloro compounds. The total number of monochloro compounds (structural isomers only) formed from all these isomers is . . . . . . .

  • A
    $3$
  • B
    $4$
  • C
    $2$
  • D
    $5$

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