Consider the ground state of chromium atom (Z | vedclass

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(C) The electronic configuration of $Cr$ $(Z=24)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^1$. Azimuthal quantum number $l=1$ corresponds to $p$-orb

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$12$ and $5$

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(C) The electronic configuration of $Cr$ $(Z=24)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^5, 4s^1$. Azimuthal quantum number $l=1$ corresponds to $p$-orbitals. The electrons in $p$-orbitals are in $2p^6$ and $3p^6$,which gives $6+6 = 12$ electrons. Azimuthal quantum number $l=2$ corresponds to $d$-orbitals. The electrons in $d$-orbitals are in $3d^5$,which gives $5$ electrons. Therefore,the number of electrons with $l=1$ is $12$ and with $l=2$ is $5$.

Consider the ground state of chromium atom $(Z=24)$. How many electrons are with Azimuthal quantum number $l=1$ and $l=2$ respectively?

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