Consider the given reaction:
$CH_3-CO-CH_3 \xrightarrow{C_6H_5COOOH} CH_3-COO-CH_3$
The above reaction is known as:
$CH_3-CO-CH_3 \xrightarrow{C_6H_5COOOH} CH_3-COO-CH_3$
The above reaction is known as:
- ABaeyer-Villiger oxidation
- BOppenauer oxidation
- CPeriodate oxidation
- DPeroxide oxidation
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Which of the following will show the haloform reaction?
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$I.$ It is reduced to methyl phenyl carbinol by sodium and ethanol.
$II.$ It is oxidized to benzoic acid with acidic $KMnO_4$.
$III.$ It does not undergo electrophilic substitution reactions (like nitration at the $m$-position).
$IV.$ It does not give the iodoform test with iodine and alkali.
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$II.$ It is oxidized to benzoic acid with acidic $KMnO_4$.
$III.$ It does not undergo electrophilic substitution reactions (like nitration at the $m$-position).
$IV.$ It does not give the iodoform test with iodine and alkali.
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$(II)$ $CH_3-CO-CH_3$
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$(IV)$ $Ph-CO-CH_2-CH_3$
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View SolutionWhich of the following reagent$(s)$ is/are used for the given conversion?
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