Consider the following transformation involvi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The overall rate constant is given by $k = \frac{k_1 k_2}{k_3}$.Using the Arrhenius equation $k = A e^{\frac{-E_a}{RT}}$,we can write:$A e^{\frac{

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) The overall rate constant is given by $k = \frac{k_1 k_2}{k_3}$.Using the Arrhenius equation $k = A e^{\frac{-E_a}{RT}}$,we can write:$A e^{\frac{-E_a}{RT}} = \frac{A_1 e^{\frac{-E_{a_1}}{RT}} \cdot A_2 e^{\frac{-E_{a_2}}{RT}}}{A_3 e^{\frac{-E_{a_3}}{RT}}}$$A e^{\frac{-E_a}{RT}} = \frac{A_1 A_2}{A_3} e^{\frac{-(E_{a_1} + E_{a_2} - E_{a_3})}{RT}}$Comparing the exponents,we get the overall activation energy expression:$E_a = E_{a_1} + E_{a_2} - E_{a_3}$Given $E_a = 400 \ kJ \ mol^{-1}$,$E_{a_1} = 300 \ kJ \ mol^{-1}$,and $E_{a_2} = 200 \ kJ \ mol^{-1}$:$400 = 300 + 200 - E_{a_3}$$400 = 500 - E_{a_3}$$E_{a_3} = 500 - 400 = 100 \ kJ \ mol^{-1}$.

Step	Rate constant $(s^{-1})$	Activation energy $(kJ \ mol^{-1})$
$1$	$k_1$	$300$
$2$	$k_2$	$200$
$3$	$k_3$	$Ea_3$

Similar Questions

Define the following terms:
$1.$ Effective collision
$2.$ Probability or steric factor $(P)$

Which of the following statements is true for a catalyst?

Explain: How is the value of activation energy determined based on the Arrhenius equation?

In the Arrhenius equation,the fraction of molecules having energy equal to or greater than the activation energy at a given temperature is represented by .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module