Consider the following sequence of reactions: | vedclass

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(C) $1$. The starting material is $2-	ext{benzylbenzoic acid}$.$2$. Treatment with $SOCl_2$ converts the carboxylic acid group into an acid chloride

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$9,10-$Dihydroanthracene

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(C) $1$. The starting material is $2-	ext{benzylbenzoic acid}$.$2$. Treatment with $SOCl_2$ converts the carboxylic acid group into an acid chloride $(-COCl)$.$3$. Subsequent treatment with anhydrous $AlCl_3$ induces an intramolecular Friedel-Crafts acylation,forming the cyclic ketone,anthraquinone (compound $A$).$4$. The final step uses Clemmensen reduction $(Zn-Hg, 	ext{Conc. } HCl)$,which reduces the carbonyl group $(C=O)$ to a methylene group $(-CH_2-)$.$5$. The reduction of anthraquinone yields $9,10-	ext{dihydroanthracene}$ (compound $B$).

Consider the following sequence of reactions:
$2-\text{benzylbenzoic acid}$ $\xrightarrow[2. \text{anhyd. } AlCl_3]{1. SOCl_2} A$ $\xrightarrow{Zn-Hg, \text{Conc. } HCl} B$
The end product $(B)$ is:

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Consider the following sequence of reactions:$2-\text{benzylbenzoic acid}$ $\xrightarrow[2. \text{anhyd. } AlCl_3]{1. SOCl_2} A$ $\xrightarrow{Zn-Hg, \text{Conc. } HCl} B$The end product $(B)$ is: