Consider the following sequence of reactions | vedclass

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(C) $1$. Sequence of reactions: Benzene $\xrightarrow{CH_3Cl/AlCl_3}$ Toluene $\xrightarrow{Cl_2/FeCl_3}$ p-chlorotoluene $\xrightarrow{K_2Cr_2O_7/H_2

Vedclass · Accepted Answer

$61$

Vedclass · Answer

(C) $1$. Sequence of reactions: Benzene $\xrightarrow{CH_3Cl/AlCl_3}$ Toluene $\xrightarrow{Cl_2/FeCl_3}$ p-chlorotoluene $\xrightarrow{K_2Cr_2O_7/H_2SO_4}$ p-chlorobenzoic acid $(X)$.$2$. Reaction with $NaHCO_3$: $R-COOH + NaHCO_3 ightarrow R-COONa + H_2O + CO_2 \uparrow$.$3$. At $STP$,$1 	ext{ mole}$ of gas occupies $22.4 \ dm^3$. Therefore,$11.2 \ dm^3$ of $CO_2$ corresponds to $0.5 	ext{ moles}$.$4$. Since $1 	ext{ mole}$ of acid reacts to produce $1 	ext{ mole}$ of $CO_2$,we require $0.5 	ext{ moles}$ of p-chlorobenzoic acid $(C_7H_5ClO_2)$.$5$. Molar mass of p-chlorobenzoic acid $(C_7H_5ClO_2)$ = $(7 	imes 12) + (5 	imes 1) + 35.5 + (2 	imes 16) = 84 + 5 + 35.5 + 32 = 156.5 	ext{ g/mol}$.$6$. Mass of acid required $(P)$ = $	ext{moles} 	imes 	ext{molar mass} = 0.5 	imes 156.5 = 78.25 	ext{ g}$.Note: The provided options do not contain the calculated value $78.25$. Re-evaluating the question,if the product was benzoic acid ($C_7H_6O_2$,molar mass $122 	ext{ g/mol}$),then $0.5 	imes 122 = 61 	ext{ g}$. Given the options,$61$ is the most plausible intended answer assuming the chlorine atom was not considered or a different product was implied.

Column-$I$ (Formula)	Column-$II$ (General Name) and Column-$III$ ($IUPAC$ Name)
$(A)$ $HCOOH$	$(i)$ Succinic acid,$(x)$ Methanoic acid
$(B)$ $CH_3CH_2CH_2COOH$	$(ii)$ Oxalic acid,$(y)$ Ethanedioic acid
$(C)$ $(COOH)_2$	$(iii)$ Formic acid,$(m)$ Butanedioic acid
$(D)$ $(CH_2)_2(COOH)_2$	$(iv)$ Butyric acid,$(n)$ Butanoic acid

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