Consider the following sequence of reactions: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The first step is the Gattermann-Koch reaction where benzene reacts with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3/CuCl$ to form $A

Vedclass · Accepted Answer

Acetophenone

Vedclass · Answer

(B) $1$. The first step is the Gattermann-Koch reaction where benzene reacts with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3/CuCl$ to form $A$,which is benzaldehyde $(C_6H_5CHO)$.$2$. The second step is the Claisen-Schmidt condensation reaction between benzaldehyde $(A)$ and a ketone $(B)$ in the presence of a base $(OH^-)$ to form the product,which is chalcone $(C_6H_5-CH=CH-CO-C_6H_5)$.$3$. For the formation of chalcone,the ketone $B$ must be acetophenone $(C_6H_5COCH_3)$.$4$. Therefore,the substance $B$ is acetophenone.

Test	$C$	$D$
Ceric ammonium nitrate Test	Positive	Positive
Lucas Test	Turbidity obtained after five minutes	Turbidity obtained immediately
Iodoform Test	Positive	Negative

Consider the following sequence of reactions:
$Benzene$ $\xrightarrow{CO, HCl, \text{anhydrous } AlCl_3/CuCl} A$ $\xrightarrow{B, OH^-, 293 K} \text{Chalcone (1,3-diphenylprop-2-en-1-one)}$
The substance $B$ is:

Similar Questions

Identify the pair of compounds which can be distinguished by the iodoform test.

Identify the product formed in the following reaction: $CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) \ H_3O^{+}]{(i) \ LiAlH_4} \text{Product}$

Which of the following compounds can show an aldol condensation reaction?

Identify the product of the following reaction: $CH_3-CH=CH-CH_2-C \equiv N \xrightarrow[H_3O^{+}]{\text{DIBAL-H}} \text{Product}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following sequence of reactions:$Benzene$ $\xrightarrow{CO, HCl, \text{anhydrous } AlCl_3/CuCl} A$ $\xrightarrow{B, OH^-, 293 K} \text{Chalcone (1,3-diphenylprop-2-en-1-one)}$The substance $B$ is: