Consider the following sequence of reactions. | vedclass

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(A) The reaction sequence involves the acid-catalyzed rearrangement of diazoaminobenzene to $p$-aminoazobenzene.$1$. The starting material is diazoami

Vedclass · Accepted Answer

$21$

Vedclass · Answer

(A) The reaction sequence involves the acid-catalyzed rearrangement of diazoaminobenzene to $p$-aminoazobenzene.$1$. The starting material is diazoaminobenzene $(C_{12}H_{11}N_3)$.$2$. Upon treatment with $HCl$ and aniline,it undergoes a rearrangement reaction known as the diazoamino-to-aminoazo rearrangement.$3$. The yellow product $(X)$ formed is $p$-aminoazobenzene,which has the chemical formula $C_{12}H_{11}N_3$.$4$. The molar mass of $C_{12}H_{11}N_3$ is $(12 	imes 12) + (11 	imes 1) + (3 	imes 14) = 144 + 11 + 42 = 197$ g/mol.$5$. The percentage of nitrogen in the product is $\frac{	ext{Total mass of N}}{	ext{Molar mass of X}} 	imes 100 = \frac{42}{197} 	imes 100 \approx 21.32\%$.$6$. Rounding to the nearest integer,we get $21\%$.

Consider the following sequence of reactions. The percentage of nitrogen in the yellow product $(X)$ formed is . . . . . . %. (Nearest Integer) (Given Molar mass in g mol$^{-1}$ $H$:$1$,$C$:$12$,$N$:$14$)

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