Consider the following sequence for aspartic | vedclass

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(B) For an acidic amino acid like aspartic acid,the isoelectric point $(pI)$ is calculated as the average of the two $pK_a$ values that flank the zwit

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$2.77$

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(B) For an acidic amino acid like aspartic acid,the isoelectric point $(pI)$ is calculated as the average of the two $pK_a$ values that flank the zwitterionic form.
The zwitterionic form of aspartic acid exists between the first deprotonation of the $\alpha$-carboxyl group $(pK_1 = 1.88)$ and the deprotonation of the side-chain carboxyl group $(pK_R = 3.65)$.
$pI = \frac{pK_1 + pK_R}{2}$
$pI = \frac{1.88 + 3.65}{2} = \frac{5.53}{2} = 2.765 \approx 2.77$

Consider the following sequence for aspartic acid:
$H_3N^+-CH(COOH)-CH_2COOH \leftrightarrow{pK_1=1.88} H_3N^+-CH(COO^-)-CH_2COOH \leftrightarrow{pK_R=3.65} H_3N^+-CH(COO^-)-CH_2COO^- \leftrightarrow{pK_2=9.60} H_2N-CH(COO^-)-CH_2COO^-$
The $pI$ (isoelectric point) of aspartic acid is:

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Consider the following sequence for aspartic acid: $H_3N^+-CH(COOH)-CH_2COOH \leftrightarrow{pK_1=1.88} H_3N^+-CH(COO^-)-CH_2COOH \leftrightarrow{pK_R=3.65} H_3N^+-CH(COO^-)-CH_2COO^- \leftrightarrow{pK_2=9.60} H_2N-CH(COO^-)-CH_2COO^-$ The $pI$ (isoelectric point) of aspartic acid is: