Consider the following reaction:CO_{(g)} + 1/ | vedclass

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(A) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta E)$ is given by the equation: $\Delta H = \Delta E + \De

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$\Delta H = \Delta E - 0.5 \, RT$

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(A) The relationship between enthalpy change $(\Delta H)$ and internal energy change $(\Delta E)$ is given by the equation: $\Delta H = \Delta E + \Delta n_g RT$.For the reaction $CO_{(g)} + 1/2 O_{2_{(g)}} 	o CO_{2_{(g)}}$,the change in the number of moles of gaseous species $(\Delta n_g)$ is calculated as:$\Delta n_g = (	ext{moles of gaseous products}) - (	ext{moles of gaseous reactants})$$\Delta n_g = 1 - (1 + 0.5) = -0.5$.Substituting this value into the equation:$\Delta H = \Delta E + (-0.5) RT$$\Delta H = \Delta E - 0.5 \, RT$.

Consider the following reaction:
$CO_{(g)} + 1/2 O_{2_{(g)}} \to CO_{2_{(g)}}$
How are $\Delta E$ and $\Delta H$ related for the reaction?

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Consider the following reaction:$CO_{(g)} + 1/2 O_{2_{(g)}} \to CO_{2_{(g)}}$How are $\Delta E$ and $\Delta H$ related for the reaction?