Consider the following reaction sequence:(CH_ | vedclass

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(C) Step $1$: Ozonolysis of $2-$methylpropene $(CH_3)_2C=CH_2$ gives acetone $(CH_3COCH_3)$ and formaldehyde $(HCHO)$.$(CH_3)_2C=CH_2 \xrightarrow[	e

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but$-3-$en$-2-$one

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(C) Step $1$: Ozonolysis of $2-$methylpropene $(CH_3)_2C=CH_2$ gives acetone $(CH_3COCH_3)$ and formaldehyde $(HCHO)$.$(CH_3)_2C=CH_2 \xrightarrow[	ext{(2) } Zn/H_2O]{	ext{(1) } O_3} CH_3COCH_3 (X) + HCHO (Y)$Step $2$: The reaction of acetone with formaldehyde in the presence of dilute $NaOH$ and heat is an aldol condensation reaction.Acetone has $\alpha$-hydrogens,so it acts as the nucleophile,and formaldehyde acts as the electrophile.The product formed is $4-$hydroxybutan$-2-$one $(CH_3COCH_2CH_2OH)$.Upon heating $(\Delta)$,it undergoes dehydration to form but$-3-$en$-2-$one $(CH_3COCH=CH_2)$.However,the question asks for the product '$Z$' formed after the reaction with dilute $NaOH$ and $\Delta$. The aldol product is $4-$hydroxybutan$-2-$one,and the dehydrated product is but$-3-$en$-2-$one.Given the options,the $IUPAC$ name of the final dehydrated product '$Z$' is but$-3-$en$-2-$one.

Consider the following reaction sequence:
$(CH_3)_2C=CH_2 \xrightarrow[\text{(2) } Zn/H_2O]{\text{(1) } O_3} X + Y$
$X + Y \xrightarrow[\text{(2) } \Delta]{\text{(1) dil. } NaOH} Z$
The $IUPAC$ name of '$Z$' is

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Consider the following reaction sequence:$(CH_3)_2C=CH_2 \xrightarrow[\text{(2) } Zn/H_2O]{\text{(1) } O_3} X + Y$$X + Y \xrightarrow[\text{(2) } \Delta]{\text{(1) dil. } NaOH} Z$The $IUPAC$ name of '$Z$' is