Consider the following reaction sequence:p-Ni | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The reduction of $p$-nitrotoluene with $H_2/Pd$ or $Sn/HCl$ gives $p$-toluidine $(Q)$. Thus,$P$ can be $H_2/Pd$ or $Sn/HCl$.$2$. The reaction

Vedclass · Accepted Answer

$A, B, C$

Vedclass · Answer

(B) $1$. The reduction of $p$-nitrotoluene with $H_2/Pd$ or $Sn/HCl$ gives $p$-toluidine $(Q)$. Thus,$P$ can be $H_2/Pd$ or $Sn/HCl$.$2$. The reaction of $p$-toluidine $(Q)$ with $NaNO_2/HCl$ or $HNO_2$ at $0-5^{\circ}C$ gives $p$-toluenediazonium chloride $(S)$. Thus,$R$ is correct in both $(A)$ and $(B)$.$3$. Hydrolysis of $S$ with $H_2O$ gives $p$-cresol $(T)$.$4$. Reaction of $S$ with $H_3PO_2$ or $CH_3CH_2OH$ removes the diazonium group to give toluene. Subsequent oxidation of the methyl group with $KMnO_4/KOH, \Delta$ gives benzoic acid. Thus,$U$ is correct in both $(A)$ and $(C)$.$5$. Evaluating the options:- $(A)$ is correct: $P, R, U$ are correct.- $(B)$ is correct: $P, R, S$ are correct.- $(C)$ is correct: $S, T, U$ are correct.- $(D)$ is incorrect: $Q$ is $p$-toluidine,not $p$-nitrobenzoic acid.Therefore,the correct combination is $(A, B, C)$.

Similar Questions

Identify $A$ and $B$ in the following reaction sequence:
Aniline $\xrightarrow[KCN]{NaNO_2/HCl} (A)$ $\xrightarrow{SnCl_2/HCl/H_3O^+} (B)$

Primary and secondary amines can be distinguished by $:-$

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$
Butter yellow is the product of the above reaction.

Which of the following sets of reagents, used in the order shown, would enable the preparation of $p$-chlorophenol from $p$-chloronitrobenzene?

The following transformation can be accomplished by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module