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(C) The reaction of $Zn$ with dilute $HNO_3$ is:$4Zn   10HNO_3 (	ext{dil.}) 	o 4Zn(NO_3)_2   N_2O   5H_2O$Thus,the gas $(P)$ is $N_2O$ (nitrous oxid

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Forms Brown ring with $FeSO_4$ solution

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(C) The reaction of $Zn$ with dilute $HNO_3$ is:$4Zn   10HNO_3 (	ext{dil.}) 	o 4Zn(NO_3)_2   N_2O   5H_2O$Thus,the gas $(P)$ is $N_2O$ (nitrous oxide).$1.$ $N_2O$ is a neutral oxide,so it gives a neutral solution in water.$2.$ $N_2O$ contains $33.3\%$ oxygen by mass,which is higher than the oxygen content in air $(\approx 21\%)$.$3.$ The brown ring test is given by $NO$ gas,not by $N_2O$. Therefore,the statement that $N_2O$ forms a brown ring with $FeSO_4$ is incorrect.

Consider the following reaction and select the incorrect statement about gas $(P)$:
$Zn + HNO_3 (\text{Dilute}) \to Zn(NO_3)_2 + P \uparrow $

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Consider the following reaction and select the incorrect statement about gas $(P)$:$Zn + HNO_3 (\text{Dilute}) \to Zn(NO_3)_2 + P \uparrow $