Consider the following reaction:
$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$
The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$

  • A
    $104$
  • B
    $111.5$
  • C
    $90.2$
  • D
    $111.0$

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