Consider the following reaction: (Cyclohexyl) | vedclass

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(C) The given reaction involves the conversion of (cyclohexyl)methyl chloride to $1-$(methoxymethyl)cyclohex$-1-$ene using sodium methoxide $(CH_3ONa)

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$E_2$

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(C) The given reaction involves the conversion of (cyclohexyl)methyl chloride to $1-$(methoxymethyl)cyclohex$-1-$ene using sodium methoxide $(CH_3ONa)$.$1$. The substrate is a primary alkyl halide,but it is sterically hindered due to the cyclohexyl group attached to the $CH_2$ carbon.$2$. $CH_3ONa$ is a strong base and a strong nucleophile.$3$. The product formed is an alkene,which indicates an elimination reaction.$4$. Since the base is strong and the substrate is primary,the reaction proceeds via the $E_2$ mechanism,where the base abstracts a proton from the ring and the chloride ion leaves simultaneously to form the double bond.

Consider the following reaction:
(Cyclohexyl)methyl chloride + $CH_3ONa$ $\rightarrow$ $1-$(methoxymethyl)cyclohex$-1-$ene.
The mechanism of the reaction will be:

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Consider the following reaction: (Cyclohexyl)methyl chloride + $CH_3ONa$ $\rightarrow$ $1-$(methoxymethyl)cyclohex$-1-$ene. The mechanism of the reaction will be: