Consider the following reactant samples:I. 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The rate of reaction $r$ for a non-zero order reaction depends on the concentration of reactants. Assuming a simple second-order reaction $r = k[A

Vedclass · Accepted Answer

$III$

Vedclass · Answer

(C) The rate of reaction $r$ for a non-zero order reaction depends on the concentration of reactants. Assuming a simple second-order reaction $r = k[A][B]$,we calculate the molar concentrations $(M = mol/L)$:$I$. $[A] = 1 \ mol / 1 \ L = 1 \ M$,$[B] = 2 \ mol / 1 \ L = 2 \ M$. Rate $r_I = k(1)(2) = 2k$.$II$. $[A] = 2 \ mol / 2 \ L = 1 \ M$,$[B] = 2 \ mol / 2 \ L = 1 \ M$. Rate $r_{II} = k(1)(1) = 1k$.$III$. $[A] = 0.2 \ mol / 0.1 \ L = 2 \ M$,$[B] = 0.2 \ mol / 0.1 \ L = 2 \ M$. Rate $r_{III} = k(2)(2) = 4k$.Comparing the rates,$r_{III} > r_I > r_{II}$. Therefore,sample $III$ reacts at the highest rate.

Similar Questions

Consider the reaction,$2 NO_{2(g)} \rightarrow 2 NO_{(g)} + O_{2(g)}$. In the figure below,identify the curves $X, Y$ and $Z$ associated with the three species in the reaction.

For the reaction $N_{2(g)} + 3 H_{2(g)} \rightarrow 2 NH_{3(g)}$,what is the relation between $\frac{d[N_2]}{dt}$ and $\frac{d[H_2]}{dt}$?

For the reaction,$3A + 2B \to C + D$,the differential rate law can be written as:

Explain the rate of reaction with examples.

Why is the rate of reaction expressed as negative with respect to a reactant? Is the rate of reaction really negative?

Vedclass Test Series

Exam Paper Generator

Online Exam Module