Consider the following electronic configurati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given electronic configuration is $[Xe] 4f^{14} 5d^1 6s^2$. The principal quantum number of the outermost shell is $n = 6$,so the element belo

Vedclass · Accepted Answer

It belongs to $6^{th}$ period and $3^{rd}$ group.

Vedclass · Answer

(C) The given electronic configuration is $[Xe] 4f^{14} 5d^1 6s^2$. The principal quantum number of the outermost shell is $n = 6$,so the element belongs to the $6^{th}$ period. The last electron enters the $5d$ orbital. For $d$-block elements,the group number is calculated as $(n-1)d + ns$ electrons. Group number $= 1 + 2 = 3$. Thus,the element $P$ (Lutetium,$Lu$) belongs to the $6^{th}$ period and $3^{rd}$ group.

Consider the following electronic configuration of an element $(P)$ : $[Xe] 4f^{14} 5d^1 6s^2$. Then,the correct statement about element $P$ is:

Similar Questions

The $IUPAC$ nomenclature of an element with electronic configuration $[Rn] 5f^{14} 6d^{1} 7s^{2}$ is.

Prove that according to quantum numbers,the $6^{th}$ period contains $32$ elements.

Which of the following is the incorrect match for the atom of an element?

The $IUPAC$ symbol for the element with atomic number $108$ is

An element having atomic number $120$ has not yet been discovered. What will be its position in the long form of the periodic table?

Vedclass Test Series

Exam Paper Generator

Online Exam Module