Consider the following compounds:(I) (CH_3)_3 | vedclass

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(A) Hyperconjugation in free radicals occurs through the $\alpha$-hydrogen atoms present on the carbon atom adjacent to the radical carbon atom.In str

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$III$ only

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(A) Hyperconjugation in free radicals occurs through the $\alpha$-hydrogen atoms present on the carbon atom adjacent to the radical carbon atom.In structure $(I)$,the radical carbon is attached to a tert-butyl group and a phenyl group. There are no $\alpha$-hydrogens on the carbon adjacent to the radical center.In structure $(II)$,the radical carbon is attached to three phenyl groups. There are no $\alpha$-hydrogens.In structure $(III)$,the radical carbon is part of a bicyclic system and is attached to a $-CH_3$ group. The carbon atom adjacent to the radical carbon has an $\alpha$-hydrogen atom,which allows for hyperconjugation.Therefore,hyperconjugation occurs in structure $(III)$ only.

Consider the following compounds:
$(I)$ $(CH_3)_3C-CH^{\bullet}-C_6H_5$
$(II)$ $(C_6H_5)_3C^{\bullet}$
$(III)$ $2$-methylbicyclo$[2.2.1]$hept$-2-$yl radical (as shown in the image)
Hyperconjugation occurs in:

Similar Questions

Among the given compounds,choose the two that yield the same carbocation on ionization.

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Consider the following compounds:$(I)$ $(CH_3)_3C-CH^{\bullet}-C_6H_5$$(II)$ $(C_6H_5)_3C^{\bullet}$$(III)$ $2$-methylbicyclo$[2.2.1]$hept$-2-$yl radical (as shown in the image)Hyperconjugation occurs in: