Consider the following compound (X):H-C equiv | vedclass

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(D) The stability of carbon radicals depends on resonance and hyperconjugation.$1.$ Position $II$ forms a propargyl radical $(HC \equiv C-CH^{\bullet}

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$II, I$

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(D) The stability of carbon radicals depends on resonance and hyperconjugation.$1.$ Position $II$ forms a propargyl radical $(HC \equiv C-CH^{\bullet}-CH(CH_3)_2)$,which is resonance-stabilized by the adjacent triple bond.$2.$ Position $III$ forms a tertiary radical,which is stabilized by hyperconjugation.$3.$ Position $IV$ forms a primary radical,which is less stable than the tertiary radical.$4.$ Position $I$ forms an $sp$-hybridized radical $(C^{\bullet} \equiv C-CH_2-CH(CH_3)_2)$,which is highly unstable due to the high $s$-character of the $sp$ orbital.Comparing the stability: The resonance-stabilized radical at $II$ is the most stable,and the $sp$-hybridized radical at $I$ is the least stable.Therefore,the correct order is $II$ (most stable) and $I$ (least stable).

Consider the following compound $(X)$:
$H-C \equiv C-CH_2-CH(CH_3)-CH_3$
The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are:

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Consider the following compound $(X)$:$H-C \equiv C-CH_2-CH(CH_3)-CH_3$The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are: