(B) For an elementary reaction $A_{(g)} + B_{(g)} \rightarrow C_{(g)} + D_{(g)}$,the rate law is given by $R_1 = k[A][B]$.Since concentration is moles

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(B) For an elementary reaction $A_{(g)} + B_{(g)} \rightarrow C_{(g)} + D_{(g)}$,the rate law is given by $R_1 = k[A][B]$.Since concentration is moles per unit volume,$R_1 = k \left( \frac{n_A}{V} \right) \left( \frac{n_B}{V} \right) = k \frac{n_A n_B}{V^2}$.When the volume is reduced to $\frac{V}{3}$,the new concentration becomes $3$ times the initial concentration.$R_2 = k [3A][3B] = 9k[A][B]$.Therefore,$R_2 = 9R_1$,which means the rate becomes $9$ times the original rate.Thus,$x = 9$.

Class 12 Chemistry Chemical Kinetics Rate of a reaction

Medium

Consider the elementary reaction $A_{(g)} + B_{(g)} \rightarrow C_{(g)} + D_{(g)}$. If the volume of the reaction mixture is suddenly reduced to $\frac{1}{3}$ of its initial volume,the reaction rate will become '$x$' times the original reaction rate. The value of $x$ is:

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A
$\frac{1}{9}$
B
$9$
C
$\frac{1}{3}$
D
$3$

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Chemical Kinetics

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Rate of a reaction

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In a pseudo first order reaction in water,the following results were obtained:

$t / s$ $0$ $30$ $60$ $90$

$[A] / mol \ L^{-1}$ $0.55$ $0.31$ $0.17$ $0.085$

Calculate the average rate of reaction between the time interval $30$ to $60 \ s$.

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In a reaction,$2 A \rightarrow \text{Products}$,the concentration of $A$ decreases from $0.5 \ mol \ L^{-1}$ to $0.4 \ mol \ L^{-1}$ in $10 \ minutes$. Calculate the rate during this interval?

Medium

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For the reaction $2SO_2 + O_2 \to 2SO_3$,the rate of disappearance of $O_2$ is $2.0 \times 10^{-4} \ mol \ L^{-1}s^{-1}$. The rate of appearance of $SO_3$ is:

Medium

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For the reaction $N_2 + 3H_2 \to 2NH_3$,if $\frac{\Delta [NH_3]}{\Delta t} = 2 \times 10^{-4} \ mol \ L^{-1} s^{-1}$,the value of $\frac{-\Delta [H_2]}{\Delta t}$ would be

Medium

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Select the correct reaction for the given rate: $\text{rate} = -\frac{1}{6} \frac{d[A]}{dt} = -\frac{1}{4} \frac{d[B]}{dt} = \frac{1}{3} \frac{d[C]}{dt} = \frac{1}{4} \frac{d[D]}{dt}$

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$t / s$	$0$	$30$	$60$	$90$
$[A] / mol \ L^{-1}$	$0.55$	$0.31$	$0.17$	$0.085$

Consider the elementary reaction $A_{(g)} + B_{(g)} \rightarrow C_{(g)} + D_{(g)}$. If the volume of the reaction mixture is suddenly reduced to $\frac{1}{3}$ of its initial volume,the reaction rate will become '$x$' times the original reaction rate. The value of $x$ is:

Similar Questions

In a pseudo first order reaction in water,the following results were obtained: $t / s$ $0$ $30$ $60$ $90$ $[A] / mol \ L^{-1}$ $0.55$ $0.31$ $0.17$ $0.085$ Calculate the average rate of reaction between the time interval $30$ to $60 \ s$.

In a reaction,$2 A \rightarrow \text{Products}$,the concentration of $A$ decreases from $0.5 \ mol \ L^{-1}$ to $0.4 \ mol \ L^{-1}$ in $10 \ minutes$. Calculate the rate during this interval?

For the reaction $2SO_2 + O_2 \to 2SO_3$,the rate of disappearance of $O_2$ is $2.0 \times 10^{-4} \ mol \ L^{-1}s^{-1}$. The rate of appearance of $SO_3$ is:

For the reaction $N_2 + 3H_2 \to 2NH_3$,if $\frac{\Delta [NH_3]}{\Delta t} = 2 \times 10^{-4} \ mol \ L^{-1} s^{-1}$,the value of $\frac{-\Delta [H_2]}{\Delta t}$ would be

Select the correct reaction for the given rate: $\text{rate} = -\frac{1}{6} \frac{d[A]}{dt} = -\frac{1}{4} \frac{d[B]}{dt} = \frac{1}{3} \frac{d[C]}{dt} = \frac{1}{4} \frac{d[D]}{dt}$

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In a pseudo first order reaction in water,the following results were obtained:

$t / s$ $0$ $30$ $60$ $90$

$[A] / mol \ L^{-1}$ $0.55$ $0.31$ $0.17$ $0.085$

Calculate the average rate of reaction between the time interval $30$ to $60 \ s$.