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(D) Step $1$: The reaction of $4$-hydroxybenzaldehyde with $Br_2$ leads to electrophilic aromatic substitution at the ortho positions relative to the

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$3,5-$dibromo$-4-$hydroxybenzonitrile

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(D) Step $1$: The reaction of $4$-hydroxybenzaldehyde with $Br_2$ leads to electrophilic aromatic substitution at the ortho positions relative to the $-OH$ group,forming $3,5$-dibromo-$4$-hydroxybenzaldehyde (Product $A$).Step $2$: The reaction of $A$ with $NH_2OH$ (hydroxylamine) converts the aldehyde group $(-CHO)$ into an oxime group $(-CH=N-OH)$,forming $3,5$-dibromo-$4$-hydroxybenzaldehyde oxime (Product $B$).Step $3$: The reaction of $B$ with $P_2O_5$ (a dehydrating agent) causes the dehydration of the oxime group to a nitrile group $(-CN)$,yielding $3,5$-dibromo-$4$-hydroxybenzonitrile (Product $C$).

$I. HNO_3$	$II. NH_2NH_2 / OH^-$
$III. 2[Ag(NH_3)_2]^+$	$IV. NaOH$

Consider the above reaction sequence,the Product $'C'$ is

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