Consider the following molecules:Glucose (K), | vedclass

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(A) $1$. Epimers are diastereomers that differ in configuration at only one chiral center. Glucose $(K)$ and Mannose $(L)$ are $C-2$ epimers. Glucose

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$(K, L) - (N, O)$

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(A) $1$. Epimers are diastereomers that differ in configuration at only one chiral center. Glucose $(K)$ and Mannose $(L)$ are $C-2$ epimers. Glucose $(K)$ and Galactose $(M)$ are $C-4$ epimers.$2$. Anomers are a special type of epimers that differ in configuration at the anomeric carbon ($C-1$ in aldoses). $\alpha-Glucose$ $(N)$ and $\beta-Glucose$ $(O)$ are anomers of each other.$3$. Looking at the options,$(K, L)$ represents an epimer pair and $(N, O)$ represents an anomer pair. Since option $(A)$ is $(K, L) - (N, O)$,this is the correct set.

Consider the following molecules:
Glucose $(K)$,Mannose $(L)$,Galactose $(M)$,$\alpha-Glucose$ $(N)$,$\beta-Glucose$ $(O)$
The correct set of epimer and anomer is respectively:
Epimer - Anomer

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Consider the following molecules:Glucose $(K)$,Mannose $(L)$,Galactose $(M)$,$\alpha-Glucose$ $(N)$,$\beta-Glucose$ $(O)$The correct set of epimer and anomer is respectively:Epimer - Anomer