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(D) For scientist $A$,who goes down into a mine at depth $d$,the acceleration due to gravity is given by $g' = g(1 - d/R)$. As $d$ increases,$g'$ decr

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Each decreases at different rates

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(D) For scientist $A$,who goes down into a mine at depth $d$,the acceleration due to gravity is given by $g' = g(1 - d/R)$. As $d$ increases,$g'$ decreases.For scientist $B$,who goes up in a balloon to a height $h$,the acceleration due to gravity is given by $g' = g(1 - 2h/R)$ (for $h \ll R$). As $h$ increases,$g'$ decreases.Since the mathematical expressions for the variation of $g$ with depth and height are different,the value of $g$ measured by each scientist decreases at different rates.

Consider Earth to be a homogeneous sphere. Scientist $A$ goes deep down in a mine and scientist $B$ goes high up in a balloon. The value of $g$ measured by

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