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(A) The angular width of the central diffraction maximum for a slit of width $a$ is given by $	heta = \frac{2\lambda}{a}$.Given that the slit is rect

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The central diffraction peak is wider in the vertical direction than the horizontal direction.

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(A) The angular width of the central diffraction maximum for a slit of width $a$ is given by $	heta = \frac{2\lambda}{a}$.Given that the slit is rectangular with width $w$ and height $h$,where $w = 2h$.The diffraction pattern is formed by the superposition of diffraction effects in the horizontal and vertical directions.The angular width in the horizontal direction is $	heta_w = \frac{2\lambda}{w}$ and in the vertical direction is $	heta_h = \frac{2\lambda}{h}$.Since $w = 2h$,we have $	heta_w = \frac{2\lambda}{2h} = \frac{\lambda}{h}$.Comparing the two,$	heta_h = \frac{2\lambda}{h}$ and $	heta_w = \frac{\lambda}{h}$,it is clear that $	heta_h > 	heta_w$.Therefore,the central diffraction peak is wider in the vertical direction than in the horizontal direction.

Consider diffraction of light through a rectangular slit which is twice as wide as it is high. Which of the following statements is true?

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